【已解决】批处理按照日期生成文件夹后放入按站点拆分的log日志，出错，求指教

memexiaolv

想处理apache生成的日志文件，每天按照一定规则提取日志放入当天的文件夹
代码：

1. @echo off
   
2. set year=%date:~0,4%
   
3. set month=%date:~5,2%
   
4. set day=%date:~8,2%
   
5. set path=E:\log\%year%\%year%-%month%\%date:~2,2%-%month%-%day%
   
6. if exist %path% (
   
7.         if exist %path%\ (
   
8.                  exit
   
9.         ) else (
   
10.                 ren "%path%" "%date:~2,2%-%month%-%day%-BAK"
    
11.         )         
    
12. )
    
13. mkdir %path%
    
14. for /f "delims=" %%a in ('type list.txt') do findstr "%%~a" test.log>>%path%\ %%a.log
    
15. pause

复制代码

list.tet文件内容：
www.test1.com
www.test2.com

test.log文件内容：
202.105.58.83 - - [03/Sep/2018:03:18:05 +0800] "GET /zw/czzxzjglqd/ HTTP/1.1" 200 92679 "www.test1.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:05 +0800] "GET /zw/ztzl/ HTTP/1.1" 200 101731 "www.test1.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:11 +0800] "GET /zw/ztzl/jlshbdcjxs/ HTTP/1.1" 200 13349 "www.test1.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:11 +0800] "GET /zw/ztzl/2018cbszx/ HTTP/1.1" 200 15388 "www.test1.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:11 +0800] "GET /zw/ztzl/bsssthj/ HTTP/1.1" 200 93780 "www.test1.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:23 +0800] "GET /zw/ztzl/hbdc/ HTTP/1.1" 200 100183 "www.test2.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:29 +0800] "GET /zw/ztzl/bszpyc/ HTTP/1.1" 200 11582 "www.test2.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:29 +0800] "GET /sy/ztzl/yyssyd/ HTTP/1.1" 200 11242 "www.test2.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"
202.105.58.83 - - [03/Sep/2018:03:18:29 +0800] "GET /zw/ggzyjy/ HTTP/1.1" 200 98161 "www.test2.com" "Mozilla/5.0 (Windows NT 5.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.109 Safari/537.36"

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①运行后出现错误，提示：'findstr' 不是内部或外部命令，也不是可运行的程序或批处理文件。for /f放在第二行就不会出现这个错误，应该是set path引起，但不知道怎么解决
②test.log并不是固定的文件，应该是access_Y%M%D%_log 按照日期每天生成的一个日志文件，这个地方该如何修改？
因为对批处理刚接触，很多东西搞不明白，请大神指教！小女子先谢过了！

flashercs

不要用系统变量 path 命名自定义变量。

1. @echo off
   
2. set "year=%date:~0,4%"
   
3. set "month=%date:~5,2%"
   
4. set "day=%date:~8,2%"
   
5. set "folder=E:\log\%year%\%year%-%month%\%date:~2,2%-%month%-%day%"
   
6. if exist "%folder%" (
   
7.         if exist "%folder%" (
   
8.                  exit /b
   
9.         ) else (
   
10.                 ren "%folder%" "%date:~2,2%-%month%-%day%-BAK"
    
11.         )         
    
12. )
    
13. mkdir "%folder%"
    
14. REM logfile=access_2018%10%10%_log
    
15. set "logfile=access_%year%%%%month%%%%day%%%_log"
    
16. for /f "delims=" %%a in ('type list.txt') do findstr /l "%%~a" "%logfile%">>"%folder%\%%a.log"
    
17. pause
    
18. exit /b

复制代码

memexiaolv

回复 2# flashercs


   
十分感谢！刚接触批处理，都不知道pacth是系统变量，问题解决，感谢！