帮修改下替换文本字符串的bat代码

2359123467

1. @echo off & setlocal EnableDelayedExpansion
   
2. for /f "delims=" %%i in ('"dir /a/s/b/on *.html"') do (
   
3. set file=%%~fi
   
4. set file=!file:/=/!
   
5. echo !file! >> sitemap.txt
   
6. )

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执行后得到结果

D:\wwwroot\xxx.cn\403.html
D:\wwwroot\xxx.cn\404.html
D:\wwwroot\xxx.cn\index.html
D:\wwwroot\xxx.cn\play.html
D:\wwwroot\xxx.cn\sitemap.html
D:\wwwroot\xxx.cn\1213\js\mode\clike\index.html
D:\wwwroot\xxx.cn\1213\js\mode\clike\scala.html

如何把结果中
D:\wwwroot\ 替换成 www.
\替换成/
每行尾部有空格 去掉

怎么改一下代码 得到我需要的格式的结果

我想要的结果是
www.xxx.cn/403.html
www.xxx.cn/404.html
www.xxx.cn/index.html
www.xxx.cn/play.html
www.xxx.cn/sitemap.html
www.xxx.cn/1213/js/mode/clike/index.html
www.xxx.cn/1213/js/mode/clike/scala.html

Batcher

1. @echo off
   
2. setlocal EnableDelayedExpansion
   
3. (for /f "delims=" %%i in ('dir /a/s/b/on *.html') do (
   
4.     set "file=%%~fi"
   
5.     set "file=!file:*:\wwwroot\=www.!"
   
6.     set "file=!file:\=/!"
   
7.     echo !file!
   
8. ))> sitemap.txt

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xp3000

1. //&cls&(dir /a/s/b/on *.html|cscript -nologo -e:jscript "%~f0")>>"导出.txt"&pause&exit
   
2. WSH.echo(WSH.StdIn.ReadAll().replace(/\\/g, '/').match(/wwwroot.+/g).join('\r\n'));

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