[己解决]批处理怎样读取指定列字符串的行？

keshun

1.txt每行格式一样，都有4列空格分开，读取第3列中包含aaa的行并整行输出，求代码，谢谢！！

Batcher

1. @echo off
   
2. setlocal enabledelayedexpansion
   
3. for /f "tokens=1-4" %%a in ('type "1.txt"') do (
   
4.     set "column3=%%c"
   
5.     if "!column3:aaa=!" neq "%%c" (
   
6.         echo %%a %%b %%c %%d
   
7.     )
   
8. )
   
9. pause

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Batcher

1. gawk "$3~/aaa/" "1.txt" > "2.txt"

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yhcfsr

1. @echo off
   
2. for /f "tokens=1-4 delims=        " %%a in ('type 1.txt^|find "aaa"') do (
   
3.         set "colum3=%%c"
   
4.         setlocal enabledelayedexpansion
   
5.         if "!colum3:aaa=!" neq "!colum3!" (endlocal&echo;%%a        %%b        %%c        %%d) else (endlocal)
   
6. )
   
7. pause

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xczxczxcz

PS 2.0+

1. (gc 1.txt)|?{$_ -match '(\S+\s+){2}a{3}'}|sc 2.txt

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