gawk怎么删除txt的注释

mio

怎么用gawk删掉txt里面！或者#开头的行

newswan

sed

1. 
   
2. sed -r -e "s/^[!#].*//" -i a.txt
   

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1. sed -r -e "/^[!#]/d" -i a.txt

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idwma

没有gawk正则的写法应该大同小异
findstr /v "^# ^!" 1.txt

cmd1152

刚刚忘记感叹号了...

1. @echo off
   
2. set file=文件.txt
   
3. (FOR /F "eol=# delims=" %%i in (%file%) do (echo %%i))>%file%.tmp
   
4. (FOR /F "eol=! delims=" %%i in (%file%.tmp) do (echo %%i))>%file%.temp
   
5. type %file%.temp>%file%
   
6. del %file%.temp %file%.tmp

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Batcher

回复 1# mio

1. gawk "!/^[!#]/" a.txt > b.txt

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