bat 截取字符串中逗号前后两个子字符串

fengyuyi

一个字符串str=“123456,abcd”
请问怎么能得到两个子字符串
str1=123456
str2=abcd
请问应该怎么编码？

DAIC

1. @echo off
   
2. set str="123456,abcd"
   
3. for /f "tokens=1-2 delims=," %%i in ("%str%") do (
   
4.     set str1=%%i
   
5.     set str2=%%j
   
6. )
   
7. echo,%str1%
   
8. echo,%str2%
   
9. pause
   

复制代码

xxpinqz

1. 
   
2.     set str1=123456
   
3.     set str2=abcd
   

复制代码

1. 
   
2.     set "str1=%%i"
   
3.     set "str2=%%j"
   

复制代码

写顺手了吧～～

fengyuyi

谢谢，2楼的和3楼的。

c755731262

1. @echo off&color f0
   
2. set str=“123456,abcd”
   
3. set str=%str:“=%
   
4. set str=%str:”=%
   
5. for /f "tokens=1,2 delims=," %%i in ("%str%") do (
   
6. set str1=%%i
   
7. set str2=%%j
   
8. )
   
9. echo str1=%str1% str2=%str2%
   
10. pause

复制代码

回复 1# fengyuyi

c755731262

1. @echo off&color f0
   
2. set str=“123456,abcd”
   
3. set str1=%str:~1,6%
   
4. set str2=%str:~8,-1%
   
5. echo %str1% %str2%
   
6. pause

复制代码

回复 1# fengyuyi