[已解决]批处理echo 有特殊符号，该如何表达？

thp2008

下面echo后面，应该如何表达,请帮你修改一下，谢谢！
总是提示，此处不该有<之类

1. @echo off
   
2. setlocal enabledelayedexpansion
   
3. for /f "delims=" %%a in ('type "URL.txt"') do (
   
4.         echo <li><a href="%%a" class="link-3" target="_blank" rel="nofollow">%%a</a></li>  >>html.txt
   
5.         )
   
6. endlocal

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qixiaobin0715

1. 输出“^ > >> & && | || < <<”
   
2. echo ^^
   
3. echo ^>
   
4. echo ^>^>
   
5. echo ^&
   
6. echo ^&^&
   
7. echo ^|
   
8. echo ^|^|
   
9. echo ^<
   
10. echo ^<^<

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qixiaobin0715

1. echo ^<li^>^<a href="%%a" class="link-3" target="_blank" rel="nofollow"^>%%a^</a^>^</li^>

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Batcher

回复 1# thp2008

1. @echo off
   
2. (for /f "delims=" %%a in ('type "URL.txt"') do (
   
3.         echo ^<li^>^<a href="%%a" class="link-3" target="_blank" rel="nofollow"^>%%a^</a^>^</li^>
   
4. ))>>html.txt

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参考：
https://mp.weixin.qq.com/s/McvY4CiR-SYGaCha7lmjIw
https://mp.weixin.qq.com/s/VZk0TmYUpFdCoWK9ZpgL0Q

77七

1. @echo off
   
2. set "str1=<li><a href="str2" class="link-3" target="_blank" rel="nofollow">str2</a></li>"
   
3. setlocal enabledelayedexpansion
   
4. (for /f "delims=" %%a in ('type "URL.txt"') do (
   
5.         echo=!str1:str2=%%a!
   
6. ))>html.txt
   
7. endlocal
   
8. pause

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aloha20200628

用 set/p="..."<nul 特殊功能》输出字符串可用双引号包裹但仅输出其内数据，如此可保全双引号之内的特殊字符不被转义。

1. 
   
2. @echo off
   
3. (for /f "delims=" %%a in (URL.txt) do (
   
4.    set/p="<li><a href="%%a" class="link-3" target="_blank" rel="nofollow">%%a</a></li>"<nul
   
5.    echo,
   
6. ))>html.txt
   

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