[文本处理] 批处理如何产生指定随机数？

pichuli1

@echo off
setlocal enabledelayedexpansion
set "svar=abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789+-*/~`_=|:;',.<>?"
set "rvar="
set num=12
:loop
set /a num-=1
set /a rand=%random%%%79
set "rvar=%rvar%!svar:~%rand%,1!"
if not %num%==0 goto loop
echo !rvar!
pause>nul

这段代码如何修改为 取数为abcdefABCDEF012345679产生8位随机数

601997526

楼主以后记得代码用code括起来

@echo off
setlocal enabledelayedexpansion
set "svar=abcdefABCDEF012345679
set "rvar="
set num=8
:loop
set /a num-=1
set /a rand=%random%%%21
set "rvar=%rvar%!svar:~%rand%,1!"
if not %num%==0 goto loop
echo !rvar!
pause>nulCOPY

CrLf

改成用for的就是这样：

@echo off&setlocal enabledelayedexpansion
set "svar=abcdefABCDEF012345679
set /a num=8,rvar=0
for /l %%a in (1 1 12) do (
        set /a rand=!random!%%21
        for %%b in (!rand!) do set "rvar=!rvar!!svar:~%%b,1!"
)
echo 密码为：!rvar:~1!
pause>nulCOPY

pichuli1

谢谢各位高手