[文本处理] 批处理如何提取/获取文本中指定字符串后面的内容？

498837077

我在文本中查找localizable，得到以下字符串
toastMessage(localizable.treasureMain_tiemout)
self.txt_numb_haves:setText(stringUtils.format(localizable.changetProLayer_have
--self.txt_count:setText(string.format(localizable.treasureMain_text2,
self.txt_count:setText(stringUtils.format(localizable.treasureMain_text2,
self.btn_golds[1]:setText(localizable.treasureMain_text4)
toastMessage(localizable.treasureMain_text1)
toastMessage(localizable.treasureMain_tiemout)
title=localizable.TreasureMain_tips1,
下面我应该怎么写，才能获取到localizable后面的字符串呢？

Nsqs

@echo off
for /f "delims=" %%1 in (a.txt)do (
set str=%%1
call set str=%%str:*localizable=%%
call echo %%str%%
)
pause
复制代码

/zhqsystem/zhq

回复 1# 498837077
直接提取%%~xi替换括号为空,自己编吧

codegay

看起来就是某种语编程语言的语法。。。居然需要用批处理