[问题求助] 这个shell脚本在干什么

netdzb

$ ls *.txt -1 | sed -e s/.exe/\&\!/g
                -1                            ~~~
这两个地方没看懂，谢谢。

Batcher

回复 3# netdzb


http://www.gnu.org/software/sed/ ... _0022s_0022-Command
The replacement can contain \n (n being a number from 1 to 9, inclusive) references, which refer to the portion of the match which is contained between the nth \( and its matching \). Also, the replacement can contain unescaped & characters which reference the whole matched portion of the pattern space.

netdzb

回复 2# Batcher

后面加了个感叹号：
\&\!

前面的符号表示增加的意思吗？

Batcher

ls 默认每行显示多个文件，ls -1 表示每行只显示一个文件：

# ls *.txt
1.exe.2.exe.txt  1.exe.txt  1.txt

# ls *.txt -1
1.exe.2.exe.txt
1.exe.txt
1.txt

后面的 sed 替换是在exe后面加了个感叹号：
# ls *.txt -1 | sed -e s/.exe/\&\!/g
1.exe!.2.exe!.txt
1.exe!.txt
1.txt

对于ls后面跟着管道的情况，-1参数是多余的，有没有无所谓。