[文本处理] [已解决]批处理如何在小于10（十）/只有一位数的数字前面补零/补0/添加0

RuiIsRui

用批处理将以下字符串中小于10的数子前加上0：

2,15,20,33,56,1,07,54,89,66,23,25,27,28,29,55,56,57,5,59,6,78,74,66,08,28,9,30,52,14,15,16,2,8,4,6,15,16,13,5,9

处理后的结果为：

02,15,20,33,56,01,07,54,89,66,23,25,27,28,29,55,56,57,05,59,06,78,74,66,08,28,09,30,52,14,15,16,02,08,04,06,15,16,13,05,09

处理后次序不能打乱，还是和处理前一样横排，不要竖排，不要分段！

[ 本帖最后由 RuiIsRui 于 2009-8-2 19:18 编辑 ]

tireless

@echo off & setlocal enabledelayedexpansion
set var=2,15,20,33,56,1,07,54,89,66,23,25,27,28,29,55,56,57,5,59,6,78,74,66,08,28,9,30,52,14,15,16,2,8,4,6,15,16,13,5,9
for %%a in (%var%) do (
  if 1%%a lss 20 (set var0=!var0!,0%%a) else set var0=!var0!,%%a
)
set var0=%var0:~1%
echo %var0%
pause
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inittab

为了处理方便，请将字串存于a.txt

@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%a in (a.txt) do (
echo 源串:%%a
for %%b in (%%a) do (
if 1%%b lss 100 (set var=0%%b) else set var=%%b
set str=!str!,!var!
)
rem 如需要输出，请改为echo;!str:~1!>>file.txt&set str=
echo;转换:!str:~1!&set str=
)
pause
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Batcher

sed -i -e "s/^\([1-9]\),/0\1,/g" -e "s/,\([1-9]\),/,0\1,/g" -e "s/,\([1-9]\),/,0\1,/g" -e "s/,\([1-9]\)$/,0\1/g" a.txt
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第三方命令行工具 sed.exe 下载地址：
http://bbs.bathome.net/thread-1114-1-1.html

RuiIsRui

谢谢2楼 tireless！

netbenton

我也来一个

 
@echo off & setlocal enabledelayedexpansion
set var=2,15,20,33,56,1,07,54,89,66,23,25,27,28,29,55,56,57,5,59,6,78,74,66,08,28,9,30,52,14,15,16,2,8,4,6,15,16,13,5,9
set "var=,!var:,=,,!,"
for /l %%a in (0,1,9) do (set var=!var:,%%a,=,0%%a,!)
set var=!var:~1,-1!
set "var=!var:,,=,!"
echo !var!
pause
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