Batcher

回复 2# 星空独子

@echo off
setlocal enabledelayedexpansion
set n=6
for /l %%i in (%n%,-1,2) do (
    set /a m=%%i-1
    xcopy /s /e /y "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A\返修%%i" "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A\返修!m!"
    rd /s /q "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A\返修%%i"
)
xcopy /s /e /y "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A\返修1" "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A"
rd /s /q "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A\返修1"
复制代码

Batcher

回复 4# 星空独子


请参考Q-04解决乱码问题
https://mp.weixin.qq.com/s/6lbb97qUOs1sTyKJfN0ZEQ

Batcher

同时我在想能否将路径中相同的部分赋值给一个变量

试试这样：

@echo off
setlocal enabledelayedexpansion
set n=6
cd /d "C:\Users\yuyu\Desktop\模拟试验\B50001-T1-19A"
for /l %%i in (%n%,-1,2) do (
    set /a m=%%i-1
    xcopy /s /e /y "返修%%i" "返修!m!"
    rd /s /q "返修%%i"
)
xcopy /s /e /y "返修1" .
rd /s /q "返修1"
复制代码

Batcher

回复 7# 星空独子

@echo off
setlocal enabledelayedexpansion
cd /d "%~dp0"
set n=0
for /f %%i in ('dir /b /ad 返修*') do (
    set /a n+=1
)
for /l %%i in (!n!,-1,2) do (
    set /a m=%%i-1
    xcopy /s /e /y "返修%%i" "返修!m!"
    rd /s /q "返修%%i"
)
xcopy /s /e /y "返修1" .
rd /s /q "返修1"
复制代码

Batcher

回复 9# 星空独子


    可能是我没看懂你的需求，能否说下8楼代码和9楼需求之间的差异在什么地方？