Five66

这样行不？
9位十进制数字以内，只取整数部分

@echo off

set num=-888890

set hex=0x10000000000
set h=0123456789abcdef0
set bbb=0x
for /f "tokens=1 delims= " %%a in ("%num:.= %") do set aaa=%%~a
if "%aaa:~0,1%" =="-" (
set bbb=%aaa:~0,1%%bbb%
set aaa=%aaa:~1%
)
if "%aaa:~9%" neq "" echo 数值过大，不支持&pause&exit/b
setlocal enabledelayedexpansion
for %%a in (10 9 8 7 6 5 4) do (
set /a ccc=aaa/!hex:~0,%%a!
set bbb=!bbb!^^!h:~!ccc!,1^^!
set /a aaa=aaa-!ccc!*!hex:~0,%%a!
)
set ddd=!h:~%aaa%,1!
echo,%num%（只取整）的16进制字符串为：%bbb%%ddd%&endlocal&pause
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