[文本处理] 批处理命令RD删除文件夹响应时间

zhitingye

rd //s /q 删除文件夹不论文件夹大小，删除响应的时间是一样的吗？

hfxiang

回复 1# zhitingye
给你一段代码，可自行测试rd指令的耗时：

@echo off
:: 耗时测试
:: 记录开始时间
set "begin_time=%time%"

::下面放你想要计算时耗的代码
...
...
...

:: 记录结束时间
set "end_time=%time%"

:: 计算耗时
set "begin_time=%begin_time: =0%"
set "end_time=%end_time: =0%"
call :time_consuming %begin_time% %end_time% c_time ms_time

echo;耗时：%c_time% （ %ms_time% 毫秒 ）
pause
exit/b

:time_consuming <beginTimeVar> <endTimeVar> [retTimeVar] [ret_ms_Var]
setlocal
set bt=%~1
set et=%~2
set/a"ct=(1%et:~,2%-1%bt:~,2%)*360000+(1%et:~3,2%-1%bt:~3,2%)*6000+1%et:~-5,2%%et:~-2%-1%bt:~-5,2%%bt:~-2%","ct+=-8640000*(ct>>31)","hh=ct/360000","mm=(ct/6000)%%60","ss=(ct/100)%%60","ms=ct%%100"
set "hh_=0%hh%"
set "mm_=0%mm%"
set "ss_=0%ss%"
set "ms_=0%ms%"
set "consuming=%hh_:~-2%:%mm_:~-2%:%ss_:~-2%.%ms_:~-2%"
endlocal&set %3=%consuming%&set %4=%ct%&goto:eof
复制代码