[数值计算] 批处理怎样计算两个日期时间的差值？

BatCoder

开始时间：2010-01-18 01:02:03
结束时间：2011-02-19 00:00:00
希望得到的结果：1年31日22时57分57秒

Batcher

@echo off
set StartTime=2010-01-18 01:02:03
set EndTime=2011-02-19 00:00:00
set StartTime=%StartTime:-= %
set StartTime=%StartTime::= %
set EndTime=%EndTime:-= %
set EndTime=%EndTime::= %
call :DateToSecs %StartTime% StartSecs
call :DateToSecs %EndTime% EndSecs
set /a DiffSecs=EndSecs-StartSecs
set DiffSecs=%DiffSecs:-= %
set /a Y=DiffSecs/31536000
set /a D=(DiffSecs%%31536000)/86400
set /a H=(DiffSecs%%86400)/3600
set /a M=(DiffSecs%%3600)/60
set /a S=DiffSecs%%60
echo %Y%年%D%日%H%时%M%分%S%秒
goto :eof

:DateToSecs %yy% %mm% %dd% %hh% %nn% %ss% secs
setlocal ENABLEEXTENSIONS
set yy=%1&set mm=%2&set dd=%3&set hh=%4&set nn=%5&set ss=%6
if 1%yy% LSS 200 if 1%yy% LSS 170 (set yy=20%yy%) else (set yy=19%yy%)
set /a dd=100%dd%%%100,mm=100%mm%%%100
set /a z=14-mm,z/=12,y=yy+4800-z,m=mm+12*z-3,j=153*m+2
set /a j=j/5+dd+y*365+y/4-y/100+y/400-2472633
if 1%hh% LSS 20 set hh=0%hh%
if {%nn:~2,1%} EQU {p} if "%hh%" NEQ "12" set hh=1%hh%&set/a hh-=88
if {%nn:~2,1%} EQU {a} if "%hh%" EQU "12" set hh=00
if {%nn:~2,1%} GEQ {a} set nn=%nn:~0,2%
set /a hh=100%hh%%%100,nn=100%nn%%%100,ss=100%ss%%%100
set /a j=j*86400+hh*3600+nn*60+ss
endlocal&set %7=%j%&goto :EOF
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pcl_test

@echo off
set time1=2010-01-18 01:02:03
set time2=2011-02-19 00:00:00
>"%tmp%\$t.vbs" echo;WSH.echo DateDiff("s","%time1%","%time2%")
for /f %%a in ('cscript -nologo "%tmp%\$t.vbs"') do set t=%%a
set /a "y=t/31536000,d=(t %% 31536000)/86400,h=(t %% 86400)/3600,m=(t %% 3600)/60,s=t %% 60"
echo;%y%年%d%天%h%时%m%分%s%秒
pause
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