批处理怎样修改BAT文件的某一个字符串？

cj227329

@set @n=0//&dir /a-d/b/s tiger.bat|cscript.exe -nologo -e:jscript "%~f0" &pause&exit/b
while (!WSH.StdIn.AtEndOfStream) {
    file = WSH.StdIn.ReadLine();
    fso = new ActiveXObject("Scripting.FileSystemObject");
    text = fso.OpenTextFile(file,1).ReadAll();
    text = text.replace(/^ *set tiger[^\r\n]+/m, "set tiger=3m arm=1m");
    fso.OpenTextFile(file,2).Write(text);
    fso = null;
}

我想把要修改的文件名称 和修改前后的值设置为参数 传入，该怎么写，大神教下？
tiger.bat  
set tiger
set tiger=3m arm=1m    这3个

terse

1. @set @n=0//&dir /a-d/b/s tiger.bat|cscript.exe -nologo -e:jscript "%~f0" "tiger.bat" "set tiger" "set tiger=3m arm=1m" &pause&exit/b

复制代码

然后 里面 看下哦

1. 
   
2. var file = WScript.Arguments(0);
   
3. var str1 = WScript.Arguments(1);
   
4. var str2 = WScript.Arguments(2);
   
5. WScript.Echo(file + " " + str1 + " " + str2);
   

复制代码

apang

把下面代码保存为test.bat

1. @set @n=0//&dir /a-d/b/s "%~1"|cscript -nologo -e:jscript "%~f0" "%~2" "%~3" &pause&exit/b
   
2. a = WScript.Arguments(0);
   
3. b = WScript.Arguments(1);
   
4. while (!WSH.StdIn.AtEndOfStream) {
   
5.     file = WSH.StdIn.ReadLine();
   
6.     fso = new ActiveXObject("Scripting.FileSystemObject");
   
7.     re = new RegExp("^( *)" + a + "[^\\r\\n]+","im");
   
8.     text = fso.OpenTextFile(file,1).ReadAll();
   
9.     text = text.replace(re, "$1" + b);
   
10.     fso.OpenTextFile(file,2).Write(text);
    
11.     fso = null;
    
12.     re = null;
    
13. }

复制代码

然后：

1. test.bat "tiger.bat" "set tiger" "set tiger=3m arm=1m"

复制代码