[已解决]批处理如何截取字段？

oqis

a.txt

1. arv19750914003P22946
   
2. arv1980060400P2394672
   
3. arv1999092300223P22946997
   
4. .
   
5. .
   
6. .

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有十几行，我想截取前面一段输出成这样：

1. arv19750914003P22
   
2. arv1980060400P23
   
3. arv1999092300223P22
   
4. .
   
5. .

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哪位出出手~~~

DAIC

1. @echo off
   
2. setlocal enabledelayedexpansion
   
3. (for /f "tokens=1-2 delims=P" %%i in (1.txt) do (
   
4.     set suffix=%%j
   
5.     echo %%iP!suffix:~0,2!
   
6. ))>2.txt

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pcl_test

回复 1# oqis

是截取从第一个字符到p后面两个的字符吗？

愤怒的CMD

gawk -FP "gsub(substr($2,3),\"\")"

pcl_test

回复 1# oqis

1. @echo off
   
2. setlocal enabledelayedexpansion
   
3. for /f "delims=" %%a in ('type "a.txt"') do (
   
4. call :loop %%a
   
5. )
   
6. pause
   
7. :loop
   
8. set str=%1
   
9. for /l %%i in (0,1,100) do (
   
10. if "!str:~%%i,1!"=="P" set "n=%%i"
    
11. )
    
12. set /a n+=3
    
13. echo !str:~0,%n%!
    
14. goto :eof

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oqis

回复 2# DAIC
很满意 多谢~~

oqis

回复 5# pcl_test
行 谢谢了

c755731262

1. @echo off&color f0&setlocal enabledelayedexpansion
   
2. (for /f "delims=" %%h in (a.txt) do (
   
3. set str=%%h
   
4. for /l %%i in (0,1,100) do (
   
5. if "!str:~%%i,1!" == "P" (
   
6. set /a n=%%i+3
   
7. call echo %%str:~0,!n!%%
   
8. )
   
9. )
   
10. )
    
11. )>test.txt
    
12. pause

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回复 8# c755731262
刚才发错了，很抱歉