批处理如何删除前两段相同的重复ip地址只保留最先/首次/第一个出现的那个ip

idccom

AB段重复数据整行删除，这个应该怎么做。。。
原数据
120.25.105.45
180.121.255.79
113.15.188.220
120.25.11.22
222.45.233.2
182.90.37.138
119.162.70.188
182.90.22.11
125.226.224.245
112.123.9.184
125.226.11.22
112.123.138.84
处理后
120.25.105.45
180.121.255.79
113.15.188.220
222.45.233.2
182.90.37.138
119.162.70.188
125.226.224.245
112.123.9.184

回家路上

1. @echo off
   
2. for /f "tokens=1,2* delims=." %%i in ('more +8 "%~f0"') do (
   
3.         if not defined #%%i%%j echo;%%i.%%j.%%k
   
4.         set #%%i%%j=1
   
5. )
   
6. pause & exit /b

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WHY

1. @if (0)==(0) echo off
   
2. cscript //nologo //e:jscript "%~f0" < 1.txt
   
3. pause & exit
   
4. @end
   
5. 
   
6. var reg = /^(\d+\.\d+)\.\d+\.\d+$/mg;
   
7. var s = WSH.StdIn.ReadAll(), map = [];
   
8. while(arr=reg.exec(s)){if(!map[arr[1]]){map[arr[1]]=1; WSH.Echo(arr[0])}}

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WHY

1. @echo off
   
2. PowerShell -c "type 1.txt | group {$_ -replace '\d+\.\d+$'} | %%{$_.Group[0]}"
   
3. pause

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WHY

1. gawk -F"." "!a[$1"."$2]++" 1.txt

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