[文本处理] 批处理替换文本指定内容后输出如何保留行与行之间的空行

wangle33589

我准备做一个替换批处理，代码如下将"debug";替换成"run"; 但是这样替换后文本中行与行之间的空格不见了，怎么办？我不打算去除空格的
@echo off&&setlocal enabledelayedexpansion
set strold="debug";
set strnew="run";
for /f  "delims=*"  %%i in (C:\Users\Administrator\Desktop\ComFunction.class.php) do (
set var=%%i
"var=!var:"debug";="run";!"
echo !var!>>ComFunction_fin.class.php
)

wangle33589

请各路大神指点迷津

sdjnab

大神们都很忙

见与不见

@echo off
cd.>_tmp.txt
setlocal enabledelayedexpansion
for /f "tokens=1* delims=:" %%i in ('findstr /n .* jqq.txt') do (
  set xiao=%%j
  if not "!xiao!"=="" set "xiao=!xiao:注册表=!"
  >>"_tmp.txt" echo.!xiao!
)
start notepad.exe _tmp.txt
复制代码

保留空行替换

lifei259

@echo off&&setlocal enabledelayedexpansion
pushd C:\Users\Administrator\Desktop
set strold="debug";
set strnew="run";
for /f  "tokens=1* delims=:"  %%i in ('type,ComFunction.class.php^|findstr /n .*') do (
set var=%%j
"var=!var:"debug";="run";!"
echo,!var!>>new_ComFunction_fin.class.php
)
复制代码