批处理如何提取文本中的最后一个数字串？

xiandai

文本a如下:

ab 111222 bc 222333 dg 350060 ac 112231 bd

要求取出112231字符到b文本 ,数字随机,位数固定是6位

flashercs

Z.bat

1. @echo off
   
2. set file1=A.txt
   
3. set file2=B.txt
   
4. powershell -Command "[System.IO.File]::WriteAllText('%~dp0%file2%',[regex]::Match([System.IO.File]::ReadAllText('%~dp0%file1%',[System.Text.Encoding]::Default),'\d{6}','RightToLeft').Value,[System.Text.Encoding]::Default)"
   
5. pause
   
6. exit /b

复制代码

/zhqsystem/zhq

注释说明：不区分列只认最后一组纯数字

1. for /f "delims=" %%i in ('type ".\1.txt"')do (
   
2. set "$=%%i"&set "data="&set "#="&set "n="
   
3. for /l %%n in (1,1,11)do if defined $ for /f "tokens=1,* delims=  " %%y in ("!$!")do (
   
4.   set "#=%%y"&set "$=%%z"
   
5.   for /l %%n in (0,1,9)do set "#=%%n!#!"
   
6.   for /l %%n in (0,1,9)do set "#=!#:%%n=!"
   
7.   if not defined # set "data=%%y"
   
8. )
   
9. if defined data (
   
10.   for /l %%n in (0,1,6)do if /i not "!data:~%%n,1!"=="" set/a "n=%%n+1"
    
11.   if /i "!n!"=="6" echo,!data!
    
12. )
    
13. )

复制代码

cfwyy77_bat

1. $ grep -Po "\d{6}(?= [a-zA-Z]{1,}$)" a.txt >b.txt
   

复制代码

xiandai

感谢几位. 已解决