怎么从右往左提取特定字符出现后接下来的字符串

857185187

1. set var=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr
   
2. echo %var:*\=%

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这样能提取出从左往右出现第一个\字符后接下来的字符串SYSTEM\CurrentControlSet\Services\FltMgr
那么如果要从右往左 比如我想要得到HKLM\SYSTEM\CurrentControlSet\Services应该怎么实现？

wxyz0001

参考
http://bbs.bathome.net/viewthrea ... mp;page=1#pid203585

1. 
   
2. set var=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr
   
3. for /f "tokens=1-4 delims=" %%a in ("%var%") do (
   
4.         echo %%a\%%b\%%c\%%d
   
5. )
   

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pause

857185187

回复 2# wxyz0001


    如果事先不知道有几个\字符呢？

terse

1. @echo off
   
2. set "var=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr"
   
3. for /f "delims=" %%i in ("z:%var%") do  set v=%%~pi
   
4. echo;%v:*\=%
   
5. pause

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1. @echo off
   
2. set "var=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr"
   
3. call :s "x:%var%" v
   
4. echo;%a:*\=%
   
5. pause & exit
   
6. :s
   
7. set %2=%~p1

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857185187

回复 4# terse


    这是把字符串当作路径处理了吧,有没有纯文本的处理方法？ 比如当var=HKLM\SYSTEM\Current/ControlSet\Services\FltMgr就不能当作路径处理了

went

回复 5# 857185187

1. @echo off
   
2. set "key=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr"
   
3. setlocal enabledelayedexpansion
   
4. set index=0
   
5. set num=0
   
6. :loop
   
7. if not "!key:~%num%,1!"=="" (
   
8. if "!key:~%num%,1!"=="" set index=%num%
   
9.         set /a num+=1
   
10.         goto :loop
    
11. )
    
12. echo !key:~0,%index%!
    
13. pause

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terse

回复 5# 857185187

1. @echo off
   
2. set "key=HKLM\SYSTEM\CurrentControlSet\Services\FltMgr"
   
3. setlocal enabledelayedexpansion
   
4. set "s=!key!" & set "l=0"
   
5. for %%i in (128 64 32 16 8 4 2 1) do if "!s:~%%i!" neq "" set /a l+=%%i & set "s=!s:~%%i!"
   
6. for /l %%i in (0,1,!l!) do if "!key:~%%i,1!" == "" set "str=!key:~,%%i!"
   
7. echo;!str!
   
8. pause

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