求助批处理的密码破解与防范

I_lidong

RT这只是一个参考，在不知内容密码的情况下如何绕过它？？？根据站内以往帖子进行实验过
1"\\==\\"1"\\ echo
已经行不通了

1. @echo off
   
2. set /p "bx98581491042896979=账户:"
   
3. goto b3064430799256274369
   
4. :b3064430799256274369
   
5. set /p "d18444147061021922194=密码:"
   
6. goto d19857206382195013238
   
7. :d19857206382195013238
   
8. if "aa"=="%bx98581491042896979%" (goto bd1874521534104010634) else (goto db2550157793073919097) >nul 2>&1
   
9. :bd1874521534104010634
   
10. if "bb"=="%d18444147061021922194%" (goto bb3159219251294803) else (goto db2550157793073919097) >nul 2>&1
    
11. :db2550157793073919097
    
12. exit
    
13. goto :dd94204849811526640
    
14. :bb3159219251294803
    
15. echo 恭喜通过！
    
16. pause
    
17. :dd94204849811526640
    
18. >nul

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